A. complete the table if y varies B. complete the table if y varies inversely as x
1. A. complete the table if y varies B. complete the table if y varies inversely as x
Answer:
it's a B. complete the table if y varies inversely as x
2. A. Complete the table if y varies directly as x or x².B. Complete the table if y varies inversely as x
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3. A. Complete the table if y varies directly as x or x2B. Complete the table if y varies inversely as x.
Answer:
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Answer:
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4. complete the table y if varies inversely as x or x²Y | X | K | equation-2 | 3 | | | 4 | 2 | 4 | | | y=8/x | 2 | | y= 4/x
Answer:
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5. B. Complete the table ify varies inversely as xkEquationY125102061081020y =х144y =X6
Answer:
9/12k 5/10k 18/24k 27/84k 108/144 ky=6 x=1
6. Complete the table if y varies inversely as x.
Inverse Variation
The two quantities are said to be inversely proportional and each term varies inversely with the other. Inversely proportional relationships are also called inverse variations. Relationships between variables that are represented in the form of y = k/x, where x and y are two variables and k is the constant value. It states if the value of one quantity increases, then the value of the other quantity decreases.
Answers:B.
k = 30; y = [tex]\frac{30}{x}[/tex]y = 9; y = [tex]\frac{36}{x}[/tex]x = [tex]\frac{5}{2}[/tex]; k = 50y = 2; k = 24Solutions:B.
1. Given: y = 5
x = 6
Find k.
y = [tex]\frac{k}{x}[/tex]
5 = [tex]\frac{k}{6}[/tex]
(5)(6) = k
30 = k
Find the equation.
y = [tex]\frac{k}{x}[/tex]
y = [tex]\frac{30}{x}[/tex]
2. Given: x = 4
k = 36
Find y.
y = [tex]\frac{k}{x}[/tex]
y = [tex]\frac{36}{4}[/tex]
y = 9
Find the equation.
y = [tex]\frac{k}{x}[/tex]
y = [tex]\frac{36}{x}[/tex]
3. Given: y = 20
y = [tex]\frac{50}{x}[/tex]
Find k.
y = [tex]\frac{k}{x}[/tex]
y = [tex]\frac{50}{x}[/tex]
k = 50
Find x.
y = [tex]\frac{k}{x}[/tex]
20 = [tex]\frac{50}{x}[/tex]
20x = 50
[tex]\frac{20x}{20}[/tex] = [tex]\frac{50}{20}[/tex]
x = [tex]\frac{5}{2}[/tex]
4. Given: x = 12
y = [tex]\frac{24}{x}[/tex]
Find k.
y = [tex]\frac{k}{x}[/tex]
y = [tex]\frac{24}{x}[/tex]
k = 24
Find y.
y = [tex]\frac{24}{x}[/tex]
y = [tex]\frac{24}{12}[/tex]
y = 2
What is inverse variation: https://brainly.ph/question/10402361
#BrainlyEveryday
7. B. Complete the table if y varies inversely as x.уXkEquation564362050y=50 2212y =
ANSWER
y. x k. equation
5. 6. 30 y=30/x
9. 4. 36 y=36/x
20. 5/2. 50 y=50/x
2 12. 24. y=24/x
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8. B. Complete the table if y varies inversely as x
Answer:
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9. Complete the table below. Write your answer on the space prpvided A. y varies directly as x. y x k Equation 45 3 __ ______ 16 __ 2 ______ __ 6 4 ______ B. y varies inversely as x. y x k Equation 6 15 __ _______ 27 18 __ _______ 3 5 __ _______ patulong po salamat po!
Answer:
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10. complete the table if y varies inversely y x k equation 5 6 4 36 20 y=50/x 12 y=24/x
complete the table if y varies inversely
y x k equation
5 6
4 36
20 y=50/x
12 y=24/x
11. Learning Task 1: y x k Equation 30 5 8 10 18 y = 3x 72 y = 2x2 A. Complete the table if y varies directly as x or x2 B. Complete the table if y varies inversely as x. y x k Equation 5 6 4 36 20 y = 12 y = x 50 x 24
Answer:
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Step-by-step explanation:
Hope it's help
12. complete the table if y varies inversely as x.y x k equation5 6 4 3620 12 y=50/x y=24/x
Answer:
the answer is blank for the while of moment
13. B. Complete the table if y variesinversely as x.ykEquationn564362050y =1224y =
Answer:
9; Answer: equation= y= 36/x. 3) 20=50/x. x=50/20. x=5/2. Answer: x = 5/2; Answer: k= 50. 4) y=24/12. y= 2.
14. B. Complete the table if y varies inversely as x.Help me please.
Answer:
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15. Learning Task 1:A. Complete the table if y variesdirectly as x or x2FVуkEquation3081018y = 3x72y = 2x2Joint and Combined VariationJoint and combined variation involves 3directly and or inversely to each other.Joint Variation
[tex]\large\color{violet}{\overbrace{\underbrace{\tt\color{violet}{ \: \: \: \: \: \: \: \: \: \: \: \: \: Answer \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}}}[/tex]
Joint and Combined Variation
Joint and combined variation involves 3
directly and or inversely to each other.
Joint Variation
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16. If y varies inversely as x and y =10 when x=2 complete the table below
Inverse variation is a relationship between two variables in which the product is constant. When one variable increases, the other decreases in proportion so that the product is unchanged. An increase in x causes a decrease in y or vice versa, we can say that y varies inversely as x or y = k/x where k is the constant of variation.
If y varies inversely as x and y = 10 when x = 2.y = k/xk = yxk = (10)(2)k = 20y = 20/x#CarryOnLearning
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17. 1.)if y varies directly as x and y=20 when x=5, find y when X=10. Then complete the table of values and present a graph.X/ 1 / 2 / 3 / 4 / 5 /Y/ / / / / /2.) if y varies inversely as x and y when x=20, find y when x=6.X/ 1 / 2 / 3 / 4 / 5 /Y/ / / / / /
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18. B. complete the table if y varies inversely as x.
Y=ka/b
Y varies directly as x and inversely as the square of z
19. complete the table if y varies inversely as x
Yand X is you and your ex boyfriend or girlfriend
20. complete the table if y varies inversely as x
Answer:
The answers are in bold.
1. y = 5, x = 6, k = 30, Equation: y = 30 / x
2. y = 9, x = 4, k = 36, Equation: y = 36 / x
3. y = 20, x = 5 / 2, k = 50, Equation: y = 50 / x
4. y = 2, x = 12, k = 24, Equation: y = 24 / x
21. III.Apply direct or inverse variation to find the unknown values. Show your completesolution.1. If y varies directly as x and y = 20 when x = 5, find y when x =10. Then complete the table of values and present a graph.X /1/2/3/4/5/Y / / / / / /SOLUTIONS HERE:
Apply direct or inverse variation to find the unknown values. Show your complete solution.Problem:
1. If y varies directly as x and y = 20 when x = 5, find y when x =10. Then complete the table of values and present a graph.
Solution:k = constant of variation
y = kx
20 = k(5)
20/5 = k
k = 4
y = kx
y = 4(10)
y = 40
if x = 1
y = kx
y = 4(1)
y = 4
if x = 2
y = kx
y = 4(2)
y = 8
if x = 3
y = kx
y = 4(3)
y = 12
if x = 4
y = kx
y = 4(4)
y = 16
if x = 5
y = kx
y = 4(5)
y = 20
X /1/ 2/ 3/ 4/ 5/
Y /4/8/12/16/20/
#CarryOnLearning22. B. Complete the table if y varies inversely as x. Y k Equation 5 6 4 36 SO 20 12 y =
1+1 =4 PROOF
1
+
1
=
4
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23. complete the table if y varies inversely as x brainly
Answer:
wheres the table
Explanation:
because without the table ii can't answer it:(
24. Complete the table of values of y varies jointly as x and z and inversely as w
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Step-by-step explanation:
pag Ikaw ay Masaya tumawa ka
25. III. Complete the table. Refer to the problem givenbelow.1. y varies inversely as x. Whenx = 3,y =2.Find y when x = 8.2.y varies directly as x. When x = 2,y = 14.Find y when x = 10.3. z varies jointly as x and y. If z = 3 whenx = 3and y = 15, find z when x = 6 and y = 9of Value
Answer:
1.22
2.12
3.42
Step-by-step explanation:
pa breinliest
26. III. Complete the table. Refer to the problem given below.1. y varies inversely as x. When x = 3, y = 2.Find y when x = 8.2. y varies directly as x. When x = 2, y = 14.Find y when x = 10.3. z varies jointly as x and y. If z = 3 when x = 3 and y = 15, find z when x = 6 and y = 9.Kind of Variation1.2.3. Value of Constant(k) Missing valueY = _____ Y = _____Z = _____
[tex]\large{\mathcal{ANSWER:}}[/tex]
[tex]\text{Kind of Variation}[/tex]
1. Inverse Variation
2. Direct Variation
3. Joint Variation
[tex] \\ [/tex]
[tex]\text{Value of Constant(k)}[/tex]
1. 6
2. 7
3. 1/15
[tex] \\ [/tex]
[tex]\text{Missing Value}[/tex]
1. Y = 3/4
2. Y = 70
3. Z = 18/5
[tex] \\ [/tex]
[tex]\large{\mathcal{SOLUTION:}}[/tex]
1. Equation: y = k/x
Finding for the constant:
Given: y = 2 and x = 3 , k = ?
y = k/x2 = k/32×3 = k6 = kFinding for the unknown value
Given: y = ? and x = 8 , k = 6
y = k/xy = 6/8y = 3/4[tex] \\ [/tex]
2. Equation: y = kx
Finding for the constant:
Given: y = 14 and x = 2 , k = ?
y = kx14 = k(2)14/2 = k7 = kFinding for the unknown value
Given: y = ? and x = 10 , k = 7
y = kxy = 7(10)y = 70[tex] \\ [/tex]
3. Equation: z = kxy
Finding for the constant:
Given: z = 3 , x = 3 , and y = 15 , k = ?
z = kxy3 = k(3)(15)3 = k(45)3/45 = k1/15 = kFinding for the unknown value
Given: z = ? , x = 6 , and y = 9 , k = 1/15
z = kxyz = 1/15(6)(9)z = 54/15z = 18/5kind of variation1. Inverse Variation
2. Direct Variation
3. Joint Variation
value of constant (k)1. 6
2. 7
3. 1/15
missing value1. Y = 3/4
2. Y = 70
3. Z = 18/5
solution1. Equation: y = k/x
Finding for the constant:
Given: y = 2 and x = 3 , k = ?y = k/x2 = k/32×3 = k6 = kFinding for the unknown value
Given: y = ? and x = 8 , k = 6y = k/xy = 6/8y=3/42. Equation: y = kx
Finding for the constant:
Given: y = 14 and x = 2 , k = ?y = kx14 = k(2)14/2 = k7 = kFinding for the unknown value
Given: y = ? and x = 10 , k = 7y = kxy = 7(10)y = 703. Equation: z = kxy
Finding for the constant:
Given: z = 3 , x = 3 , and y = 15 , k = ?z = kxy3 = k(3)(15)3 = k(45)3/45 = k1/15 = kFinding for the unknown value
Given: z = ? , x = 6 , and y = 9 , k = 1/15z = kxyz = 1/15(6)(9)z = 54/15z = 18/527. Complete the table if y varies inversely as x.Patulong PoNonsense=Report
Answer:
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28. B. Complete The table if y varies inversely as x
Answer:
Step-by-Step Explanation
29. Y. X. K. equation5. 6 2. 3640. 8. complete the table of y varies inversely as xy= R — x
Answer:
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[tex]click \: the \: picture[/tex]#CARRY ON LEARNING.30. complete the table if y varies inversely as x brainly
Wala pong table?
Statement: y varies inversely as x
Formula: y=k/x
