4wt + 2wh + 6it + 3ih
1. 4wt + 2wh + 6it + 3ih
the answer is still the same if variables are notvthe same it shouldnt be combinethe factors of that polynomial are
(2t+h) (2w+3i)
2. 4wt + 2wh + 6it + 3ih
Answer:
It could be like this:
(4wt + 2wh)+(6it + 3ih)
Regroup or whatever to call that.
Then find their common monomial factor.
So we'll have this:
2w(2t + h) + 3i(2t + h) or (2w + 3i)(2t+h)
3. 4wt + 2wh + 6it+ 3ih
Answer:
(2t + h) (2w + 3i)
Step-by-step explanation:
4wt + 2wh + 6it + 3ih
= (4wt + 2wh) + (6it + 3ih)
= 2w (2t + h) + 3i (2t + h)
= (2t + h) (2w + 3i)
4. 4wt+2wh+6it+3ih give the correct answer with sulotion
Answer:
[tex]4tw + 2hw + (6t + 3h)i[/tex]
Step-by-step explanation:
[tex]4wt + 2wh + 6it + 3ih \\ 4tw + 2hw + 6ti + 3hi \\ 4tw + 2hw + (6t + 3h)i[/tex]
5. 4wt + 2wh + 6it + 3ih what is the answer guys? with solution..
Answer:
(3i + 2w)(h + 2t)
Step-by-step explanation:
4wt + 2wh + 6it + 3ih
3hi + 2hw + 6it + 4tw
h(3hi/h + 2hw/h) + 2t(6it/2t + 4tw/2t)
h(3i + 2w) + 2t(3i + 2w)
= (3i + 2w)(h + 2t)
6. factor this 4WT+2WH+6IT+3IH by grouping
4WT + 2WH + 6IT + 3IH
2W (2T + H) + 3I (2T + H)
(2W + 3I) (2T + H) >>>> ANSWER
7. What is the solution of 4wt+2wh+6it+3ih
Answer:
2tw+2hw+(6t+3h)i
Step-by-step explanation:
2wt+2wh+6it+3ih
2tw+2hw+6ti+3hi
8. factor 4wt+2wh+6it+3ih
Use Factoring by Group
4wt + 2wh + 6it + 3ih
[4wt + 2wh] + [6it + 3ih]
2w(2t + h) + 3i(2t + h)
= (2w + 3i)(2t + h) is the answer.
9. 8.What factoring is applicable in this expression 4wt + 2wh + 6it + 3?A.Common Monomial Factoring B. By Quadratic equtionC. By grouping D. By perfect square trinomials
Answer:
mag ml kana nalang
Step-by-step explanation:
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Basahin nyo po tas makikita nyo po ang sagot10. what is the answer of 4wt+2wh+6it+3ih
the answer is the same with the given
11. grouping technique 4wt+2wh+6it+3ihshow sulotion
Answer:
=(2t+1h) (2w+3i)
Step-by-step explanation:
= (4wt+2wh)+(6it+3ih)
= 2w(2t+1h)+3 (25+1h)
= (2t+1h) (2w+3i)
12. how to facror this: 4wt+2wh+6it+3ih
It could be like this:
(4wt + 2wh)+(6it + 3ih)
Regroup or whatever to call that.
Then find their common monomial factor.
So we'll have this:
2w(2t + h) + 3i(2t + h) or (2w + 3i)(2t+h)
13. what is the answer of the equation (4wt+2wh)+(6it+3ih)
90.60 i guess answer
14. Factoring By Grouping 1. 4wt + 2wh + 6it + 3ih= 2. 15te - 12he + 10ty - 8hy= please answer it
1. 2w (2t + h) + 3i (2t + h)
(2w + 3i) (2t + h)
2. 3e(5t - 4h) + 2y(5t - 4h)
(3e + 2y) (5t - 4h) 1. 4wt+2wh+6it+3ih =(4wt+2wh)+(6it+3ih) = 2w(2t+h)+3i(2t+h). = (2w+3i)(2t+h). 2. 15te-12he+10ty-8hy =(15te-12he)+(10ty-8hy). = 3e(5t-4h)+2y(5t-4h) =(3e+2y)(5t-4h)
15. 4wt+wh+6it+3ih waht of the answare?
cancel w, h, i, t then plus the numbers = 13
16. find out the greatest common monomial factor of (4wt+2wh)-(6it+3ih)
Answer:
(4wt+2wh)-(6it+3ih)
2w(2t+h)-3i(2h+h)
(2t+h)(2w-3i)
17. 4wt+2wh+6it+3ih farctoring and groupings
(4wt+2wh) (6it+3ih)
2w(2t+h) 3i(2t+h)
18. how to solve this 4wt+2wh+6it+3ih
just copy the question ;)
19. (4wth +2wh)+(____+3ih)
Answer:
(2w + 3i)(2t +h)
Step-by-step explanation:
basta yan yung sagot
20. factors po ng 4wt+2wh+6it+3ih
Answer:
(3i+2w)(h+2t)
Step-by-step explanation:
4wt+2wh+6it+3ih
3hi+2hw+6it+4tw
h(3i + 2w)2t(3i + 2w)
= (3i+2w)(h+2t)
21. How to solve 4wt + 2wh + 6it + 3ih
(2wh + 3ih) + (4wt + 6it)
h(2w + 3i) + (2t)(2w + 3i)
factoring out:
(2w + 3i)(h + 2t)
22. Answer of 4wt+2wh+6wt+3h
Answer:
Step-by-step explanation: copy kanalang sa kakalse mo
23. 1. 4wt+2wh+6it+3ih 2. 15te-12he+10ty-8hy 3. hv+av+he+ae 4. 10ti-8ts-15hi+12hs 5. 88fo+16ro-99fm-18rm
the factors are
1. (2w+3i) (2t+h)
2. (3e+2y) (5t-4h)
3. (v+e) (h+a)
4. (2t-3h) (5i-4s)
5. (8o-9m) (11f+2r)
hey can I ask a favor?.
24. 4wt+2wh+6it+3ih in solving in famous four words
The factors are (2w+3i)(2t+h)
25. [tex]4wt + 2wh + 6it + 3ih[/tex]groupmates
Answer:
(2t+h)(2w+3i)
Step-by-step explanation:
Factor by their GCMF
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26. what is factors of 4wt+2wh+6it+3ih
Answer:
(2t+h)(2w+3i)
27. Famous word4wt+2wh+6it+3ih
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28. Factoring by grouping 4wt+2wh+6it+3ihhv+av+he+ae18lv+6lv+24ov+8oe
4wt + 2wh + 6it + 3ih
2w (2t + h) + 3i (2t + h)
(2w + 3i) (2t + h)
hv + av + he + ae
v (h + a) + e (h + a)
(v + e) (h + a)
29. 4wt + 12wh + 6it + 3ih factoring by grouping
4wt + 12wh + 6it + 3ih
= (4wt + 12wh) ( 6it + 3ih)
=4w (1 + 3h) + 3i (2 + h)
{yung 4w (1 + 3h) + 3i (2 + h) yan po ung answer :) }
30. factor of 4 wt + 2 wh + 6it + 3ih
4 wt + 2 wh + 6it + 3ih
= 2w(2t+h) + 3i(2t+h)
= (2w+3i) (2t+h)