What is the % M/M if 10. Og of copper is added to enough zinc to produce 110g of an alloy?
1. What is the % M/M if 10. Og of copper is added to enough zinc to produce 110g of an alloy?
Answer:
all of us have questin
Explanation:
anothe one
2. what is the m/m if 10.0g of copper
Answer:
alert alert give to all is coming
Explanation:
11:00 am
good luck
3. FRANCIS HAD 7 9/10 M OF COPPER WIRE,HE USED 4 1/10 M TO FINISH THIS RADIO,WHAT PART OF THE COPPER WIRE WAS LEFT UNUSED?
Answer:
3 4/5
Step-by-step explanation:
:):):):)):):):):)
4. E. how many milliliters of 5.0 m copper sulfate solution must be added to 228 ml of water to achieve a 0.25 m copper sulfate solution
Answer:
cooper sulfate i widely used a dietary suplement for animals feed. a lab tecnician preparesa stock solution of CUSO 4 bay adding 79'g / 100 grams if water
5. A copper wire is 10 m long and has a resistance of 50 ohnm. What is its resistance if the length is reduced to 6m?
Answer:
sorry needed points
Explanation:
sorry po talga
6. what is the %m/m if 10.0g of copper is added to enough zinc to produce 110g of an alloy?
Answer:
% (m/m) = 9.09
Explanation:
% (m/m) = (mass solute/ mass solution) ×100
%(m/m) = (10.0g/ 110g) ×100
% (m/m) = 9.097. what is the % m/m of copper in an alloy when 10kg of Cu is mixed with 250 kg of Zn
Answer:
3•8%
Explanation:
Yan po sagot ko ehh!!
8. A MAXIMUM ALLOWABLE VOLTAGE DROPFOR A 70 m LENGTH OF A CERTAIN CABLETHAT CARRIES A CURRENT OF 40A IS 5 V.WHAT IS THE MINIMUM CROSS-SECTIONALAREA OF THE COPPER WIRE OF THECABLE IN SQUARE MILLIMETERS? THERESISTIVITY OF COPPER IS 1.7 x 10^-8 ohm•m
Answer:
The minimum cross-sectional area should be less than 9,520,000 mm²
Explanation:
Here, we are to solve the minimum value of the cross-sectional area of a copper wire. Since we have a given of maximum values of voltage, we will take the values less than that of the solved value since there is no range of voltage given.
Here, we will use the concept of resistance and voltage law to solve for the cross-sectional area of the copper wire.
For the formula, we will use:
1. V = IR
where
V is the voltage drop for the wire, unit is in volts
I is the current running through the wire, unit is in ampere, A
R is the resistance or property of the wire to resist the flow of current,
unit is in ohms, Ω
2. R = ρL/ A
where
ρ is the resistivity constant of any material
L is the length of the wire, unit is in meter, m
A is the cross-sectional area of the wire, unit is in m²
For the given information
V = 5 V
L = 70 m
I = 40 A
ρ = 1.7 x 10⁻⁸ Ω-m
Solving the problem
1. First, let us solve for the resistance of the wire using the first given formula.
V = IR
Then, substitute the given data
5V = (40 A) R
Divide both sides of the equation by 40A
R = 5V / 40A
R = 0.125 Ω
2. Now, let us solve for the cross-sectional area using the next given formula
R = ρL/ A
Then, substitute the given data
0.125 Ω = 1.7 x 10⁻⁸ Ω-m (70 m / A)
Cross-multiply
A = 1.7 x 10⁻⁸ Ω-m (70 m / 0.125 Ω)
A = 9.52 x 10⁻⁶ m²
A = 9,520,000 mm²
Therefore, the minimum cross-sectional area of the copper wire should be less than 9,520,000 mm².
To learn more, just click the following links:
What is resistance and its unit?https://brainly.ph/question/34901
Voltage and current relationshiphttps://brainly.ph/question/394664
#LetsStudy
9. What is the % M/M if 10.0g of copper is added to enough zinc to produce 110g of an alloy?
Answer:
percent by mass = 9.09%
Explanation:
percent by mass = (mass solute / mass solution) × 100
percent by mass = (10.0 g / 110 g) × 100
percent by mass = 9.09%
#CarryOnLearning
10. What is the M/M if 10.0g of copper is added to enough zinc to produce 110g of allo? A 9.05 B 9.09 C 9.10 D 10.00
Answer:
d
Explanation:
sorry po kung mali sinolve ko lng po
11. 1.A block of copper has a volume of 0.005 m³. The density of copper is 8,960 kg/m³. Calculate the mass of the copper block.
Answer:
ρ = 8.96 × 103 kg/m3
v = 0.005 m3
m = ρv
m = 8.96 × 103 × 0.005
m = 44.8 kg
The mass of the copper block is 44.8 kg
12. B. 75%C. 85%D. 95%10. What is the % M/M if 10.0g of copper is added to enough zinc to produce 110gof an alloy?A. 9.05%B. 9.09%C. 9.10%D. 10.00%
Answer:
the answer of the question is C
13. press- Mr. Cruz had a long copper wire from which he cut two pieces with ameasure of 0.982 m and 3.432 m. After cutting it, there was 3.23 mcopper wire left. What is the length of the wire at the start?a. What is the answer to the problem?b. What is the total length of the two smallest copper wires?
Answer:
a
Step-by-step explanation:
cause we dont know the answer of the question
and the b. is questioning the lenght of the copper
14. What is the % M/M if 10.0g of copper is added to enough zinc to produce 110g of an alloy?
Answer:
%(m/m) = 9.09%
Explanation:
Solve for the mass percent of copper.
%(m/m) = (mass solute / mass solution) × 100
%(m/m) = (10.0 g / 110 g) × 100
%(m/m) = 9.09%
#CarryOnLearning
15. what is the % M/ M if 10.0g copper is added to enough zinc to produce 110g of an alloy
10/110 x 100 = 11%
11%
16. A copper wire is 10 m long and has a resistance of 0.50 12. What is its resistance if the length is Reduced to 6 m?
Answer:
[tex]12 \div 10 = 1 \times 6 = 6[/tex]
Explanation:
yan answer
17. 13. Jun Mark used 15 m of copper wire which weighs 1 kg. If a copper wireweighs 3.5 kg, how many meters is it?A. 50 mC. 53.5 mB. 52.5 mD. 54 m
Answer:
52.5 m
Step-by-step explanation:
15 multiply by 3.5 the answer is 52.5
hope it helps
18. TRUE OR FALSE A 2 m copper wire has a higher resistance than a 4 m copper wire
Answer:
false po
Explanation:
because 4m is higher than 2m
19. what is the m/m if 10.0g of copper is added to enough zinc to produce 110g of an alloy
Answer:
Answer:
%(m/m) = 9.09%
Explanation:
Solve for the mass percent of copper.
%(m/m) = (mass solute / mass solution) × 100
%(m/m) = (10.0 g / 110 g) × 100
%(m/m) = 9.09%
20. what is the maximum length of 96 m copper wire and 136 m of aluminum wire
Answer:
1.4166666667
Step-by-step explanation:
Im not 100% sure
21. 1. Mr. Cruz had a long copper wire from which he cut two pieces with ameasure of 0.982 m and 3.432 m. After cutting it, there was 3.23 mcopper wire left. What is the length of the wire at the start?a. What is the answer to the problem?b. What is the total length of the two smallest copper wires?
Answer:
a. 7.64
b. 4.414
Step-by-step explanation:
a.
0.982 + 3.432 + 3.23
b.
0.982 + 3.432
Answer:
a. 7.644
b.?
Step-by-step explanation:
On A.
0.982+3.432= 4.414
Then add the 3.23 to 4.414
4.414+3.23= 7.644
22. Manny had a long copper wire from which he cut two pieces. One piece was 0.832 mand the other was 1.35 m. After cutting the two pieces, there was 3.9 m copper wireleft. What is the length of the wire at the start?
Answer:
[tex]0.832 + 1.35 + 3.9 = 6.082[/tex]
Step-by-step explanation:
You just add so the answer is 6.082m
23. 5. Eduard had 7 9/10 m of copper wire. He used 4 1/10 m to finish his radio. Whatpart of the copper wire was left unused?
Answer:
3 8/10 or 3 4/5
Step-by-step explanation:
sana tama at makahelp.
Answer:
6 8/10?
Step-by-step explanation:
yan sagot ko, nasa sayo na kung gagayahin mo:>
24. What is the % M/M if 10.0g if copper is added to enough zinc to produce 1 10g of an alloy
Answer:
i think the answer is a based on solutions and scientific evidence and explanation
Explanation:
copper and zinc has the same minerals so the solutions is either from both of them
25. James had 79/10 m of copper wire. Heused 41/10 m to finis his radio. How many did he have left?
Answer:
19/5 (simplify 3 4/5)
Step-by-step explanation:
79/10 - 41/10
= 38/10 ÷ 2
= 19/5 simplify 3 4/5
26. what is the percent by mass if 8. 0g copper is added to zinc to produce 100g alloy? Given:Unknown:Formula:Solution:Conclusion:
TY FOR THE POINT BRO
27. A 0.75 m long copper wire has an area of 15.53 m². what would be the resistance of the copper wire?
Answer:
copper if the length is 10 meters long and the cross. section is a 4 x 4 cm. 2 . Use 1.7241 micro ohm-cm as. the resistivity. A. 2.121 x 10. -4. Ω C. 3.431 x 10. -5. Ω.
Explanation:
28. 10. What is the % M/M if 10.Og of copper is added to enough zinc to produce 110gof an alloy?A. 9.05%B. 9.09%C. 9.10%D. 10.00%
Answer:
a. 9.05 percent i guess its
Explanation:
i do not knkw how to explain at this moment please provide specific questions with these.
29. what is the % m/m if 10.0g of copper is added to enough zinc to produce 110g of an alloy?
% ( M/M) = 9.09 %
EXPLANATION:
SOLVE FOR THE MASS PERCENT COPPER
% ( M/M ) = ( MASS SOLUTE / MASS SOLUTION ) x 100
% ( M/M ) = ( 10.0g / 110g ) x 100
% ( M/M ) = 9.09 %
HOPE IT HELPS#CARRYONLEARNING
#BRAINLY.PH
30. Mr. Reyman used 3.2 m of copper wire which weighs 0.45 kg. How many will 6 m of copper wire weigh?
0.5 is the answer
hope it may help you
Use the ratio, call X the mass of 6 m of wire 3.2 m / 0.45 kg = 6 m / X Solve for X. Or work out the mass per m. If 3.2 m = 0.45 kg then 1 m = 0.45 kg / 3 m.
