find the sum of the integers from 8 and 35
1. find the sum of the integers from 8 and 35
The sum of the integers from 8 and 35 : 602
Further explanationArithmetic sequence is an arrangement of numbers that has the same difference for consecutive pairs of numbers or it can be said that "the difference between one term and the next is a constant. (adding the same number to the next number) "
The arrangement of the numbers is like this:
[tex]\tt a,a+d,a+2d,a+3d..etc[/tex]
a = initial term
d = different (common difference)
The formula for the nth term:
[tex]\tt \boxed{\bold{x_n=a+(n-1)d}}[/tex]
While the formula for the sum of n terms:
[tex]\tt \boxed{\bold{\dfrac{1}{2}n(a+x_n)}}\\\\or\\\\\boxed{\bold{\dfrac{1}{2}n(2a+(n-1)d}}[/tex]
To calculate the number of integers between 2 numbers(the nth term), just subtract the two numbers then add 1
The number of integers between 8 and 35 :
[tex]\tt (35-8)+1=28~numbers[/tex]
So the sum of the integers from 8 and 35 :
n = 28
a = 8
xn = 35
[tex]\tt =\dfrac{1}{2}.28(8+35)\\\\=14(43)\\\\=\boxed{\bold{602}}[/tex]
Learn morecommoon difference of the sequence
https://brainly.ph/question/1721583
Insert two aritmetic means
https://brainly.ph/question/1543769
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#LetsStudy
2. find the sum of the integers from 8 to 35
Answer:
+43
Step-by-step explanation:
You just litteraly add it becuse none of them is negative
3. find the sum of the integers from 8 and 35
Answer:
602
Explanation:
Basta pinag plus ko nalang. Pede mo ding gamitan ng the sum of Arithmetic sequence since 1 common difference.
4. find the sum of the integers from 8 to 35
Answer:
the sum of the integers from 8 and 35 is 602
5. find the sum of all even integers from 8 and 35.
Answer:
602
Step-by-step explanation:
n= 35 - 7 = 28
n= 28
S = (n/2) (a+L)
= (28/2) ( 8 + 35 ) = 602
6. 4) SnC) Answer what is asked.1) Find the sum of the first 13 terms of the sequence: -3, -1,1,3,...2) Find the sum of the first 15 terms of the arithmetic sequence:10, 15, 20, 25, ...?3) Find the sum of the first 11 terms of the arithmetic sequence:-4,3, 10, 17,...?4) Find the sum of the first 19 terms of the arithmetic sequence:9, 14, 19, 24, ...?5) Find the sum of the integers from 8 and 35.6) Find the sum of all even integers from 10 to 70.7) Find the sum of all odd integers from 1 to 50.8) Find the sum of the integers from 20 to 130 and are divisible by 5.9) If the sum of the first 8 terms of an arithmetic sequence is 172 andits common difference is 3, what is the first term?10) If the sum of the first 9 terms of an arithmetic sequence is 216and its first term is 4, what is the common difference? genus??
Answer:
1. 117
2. 675
3. 341
4. 1026
5. 602
6. 1260
7. 594
8.10270
9. 44
10. 22.5
Step-by-step explanation:
7. 1. Find the sum of the integers from 8 to 35 2.Fjnd the sum of all even integers from 10 to70 3. Find the sum of all odd integers from 1 to 50
Answer:
1. 602
2. 800
3. 1275
Step-by-step explanation:
1. n= 35 - 7 = 28
n= 28
S = (n/2) (a+L)
= (28/2) ( 8 + 35 ) = 602
2. n= all even so 70 - 10 / 2 + 1 = 20
n= 20
S= (n/2) (a+L)
= (20/2) (10+70)
= 800
3. n= 50
so.
S= ( a+L /2) (n)
= ( 1 + 50 / 2) (50)
= 1275
sana makatulong godblesa
8. Find the sum of all the intergers from 8 and 35.Find the sum of all even integers from 10 to 70.Find the sum of all add integers from 1 to 50.
Answer:
420
1,240
625
Step-by-step explanation:
8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35=420
10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50+52+54+56+58+60+62+64+66+68+70=1,240
1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49=625
9. Pakisagot plsss4) Find the sum of the first 15 terms of the arithmetic sequence: 10, 15, 20, 25, ... ? 5) Find the sum of the integers from 8 and 35. 6) Find the sum of all even integers from 10 to 70.
Answer:
same question
Step-by-step explanation:
pa sagot po nyan sana p.o. yong maayus
10. 5) Find the sum of the integers from 8 and 35.
Answer:
If you mean the sum of the integers from 8 to 35 then the answer is 602
11. Answer What is asked.5) Find the sum of the integers from 8 and 35.6) Find the sum of all even integers from 10 to 70.7) Find the sum of all odd integers from 1 to 50.8) Find the sum of the integers from 20 to 130 and are divisible by 5.9) If the sum of the first 8 terms of an arithmetic sequence is 172 andits common difference is 3, what is the first term?10) If the sum of the first 9 terms of an arithmetic sequence is 216and its first term is 4, what is the common difference? genus??help me please, and need a solvings
5.599
6.4970
7.625
8.1725
9.A1
10.216
solution:
5).Sum=559
Step-by-step explanation:
a1=8
a2=9
an=35
a(n-1)=34
6).step 1 Address the formula, input parameters & values.
Input parameters & values:
The number series 2, 4, 6, 8, 10, 12, . . . . , 140.
The first term a = 2
The common difference d = 2
Total number of terms n = 70
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 70/2 x (2 + 140)
= (70 x 142)/ 2
= 9940/2
2 + 4 + 6 + 8 + 10 + 12 + . . . . + 140 = 4970
7).l=a+(n-1)d
49=1+(n-1)2
2n-2=48
2n=50
n=50/2
n=25
Sn=n/2(a+l)
=25/2(1+49)
=25/2(50)
=25(25)
=625.
8).1
Sn = 1725
Step-by-step explanation:
formulas:
last term = first term + (n-1)d
Sn = n/2 (first term + last term)
given:
d= 5. last term= 130. first term= 20. n=?
solution:
last term = first term + (n-1)d
130 = 20 + (n-1)5
130-20 = (n-1)5
110 = (n-1)5
110 = (n-1) 5
----- ----------
5 5
22 = n-1
22+1 =n
23 = n
Sn = 23/2 (20+130)
Sn = 23/2 (150)
make it easier by dividing 150 to 2 first then multiply it to 23
Sn = 23 (75)
Sn = 1725 -
9.)S8 = 8/2 [2(A1) + (8 - 1)3]
172 = 8/2 [2A1 + (7)3]
172 = 8/2 (2A1 + 21)
344 = 8 (2A1 + 21)
344 = 16A1 + 168
344 - 168 = 16A1
176 = 16 = A1
16 16
11 = A1
12. I have two questions please answer it;1. Find the sum of the first 19 term's of the arithmetic sequence:9,14,19,24,...?2.Find the sum of the integers from 8 and 35
Answer:
sun is raising at least 20 words
Answer:
1.)29
2.)602
Step-by-step explanation:
correct me if im wrong
thank you
13. 1) Find the sum of the first 13 terms of the sequence: −3, −1, 1, 3, … 2) Find the sum of the first 15 terms of the arithmetic sequence: 10, 15, 20, 25, … ? 3) Find the sum of the first 11 terms of the arithmetic sequence: −4, 3, 10, 17, … ?4) Find the sum of the first 19 terms of the arithmetic sequence: 9, 14, 19, 24, … ? 5) Find the sum of the integers from 8 and 35. 6) Find the sum of all even integers from 10 to 70. 7) Find the sum of all odd integers from 1 to 50.8) Find the sum of the integers from 20 to 130 and are divisible by 5. 9) If the sum of the first 8 terms of an arithmetic sequence is 172 and its common difference is 3, what is the first term? 10) If the sum of the first 9 terms of an arithmetic sequence is 216 and its first term is 4, what is the common difference?with solution..christiansantiago45 pls
Answer:
8
4
6
6
5
7
55
6
7
6
5
5
5
Step-by-step explanation:
thank for the points:)
Question1) Find the sum of the first 13 terms of the sequence: −3, −1, 1, 3, …
2) Find the sum of the first 15 terms of the arithmetic sequence: 10, 15, 20, 25, … ?
3) Find the sum of the first 11 terms of the arithmetic sequence: −4, 3, 10, 17, … ?
4) Find the sum of the first 19 terms of the arithmetic sequence: 9, 14, 19, 24, … ?
5) Find the sum of the integers from 8 and 35.
6) Find the sum of all even integers from 10 to 70.
7) Find the sum of all odd integers from 1 to 50.
8) Find the sum of the integers from 20 to 130 and are divisible by 5.
9) If the sum of the first 8 terms of an arithmetic sequence is 172 and its common difference is 3, what is the first term?
10) If the sum of the first 9 terms of an arithmetic sequence is 216 and its first term is 4, what is the common difference?
with solution..
Its 117−3−1+1+3+5+7+9+11
+13+15+17+19+21 = 117
80=10+(15-1)5
=10+(14)5
3413-(-4) = 7
10-3 = 7
17-10=7
102614-9= 5 19-14=5
An= 9+(19-1)5
An= 9+90
A19= 99
6021240a1= 10
a31=70
n=31 (because from 10-70 we have 31 even numbers)
s31= 31/2 (10+70)
s31= 1240
625l=a+(n-1)d
49=1+(n-1)2
2n-2=48
2n=50
n=50/2
n=25
Sn=n/2(a+l)
=25/2(1+49)
=25/2(50)
=25(25)
1275formulas:
last term = first term + (n-1)d
Sn = n/2 (first term + last term)
given:
d= 5. last term= 130. first term= 20. n=?
solution:
last term = first term + (n-1)d
130 = 20 + (n-1)5
130-20 = (n-1)5
110 = (n-1)5
110 = (n-1) 5
----- ----------
5 5
22 = n-1
22+1 =n
23 = n
Sn = 23/2 (20+130)
Sn = 23/2 (150)
make it easier by dividing 150 to 2 first then multiply it to 23
Sn = 23 (75)
11S8 = 8/2 [2(A1) + (8 - 1)3]
172 = 8/2 [2A1 + (7)3]
172 = 8/2 (2A1 + 21)
344 = 8 (2A1 + 21)
344 = 16A1 + 168
344 - 168 = 16A1
2164+5=9
9+5=14
14+5=19
19+5=24
24+5=29
29+5=34
34+5=39
39+5=44
4+9+14+19+24+29+34+38+44=
14. find the sum of the integers from 8 to 35
Answer:
602
Step-by-step explanation:
28/2 (8+35)
= 14(43)
= 602
15. 5) Find the sum of the integers from 8 and 35.
Answer:
The answer is going to be 43.
Answer:
43
Step-by-step explanation:
8+35=43
add 8 and 35 so that's why the answer is 43
16. find the sum of the integers from 8 and 35 using the sequence series
the answer is 43
i can't do it using the sequence series because I'm still also learning about integers
that's all i can give you sorry
hope it helps
17. Find the sum of the integers from 8 and 35.
Answer:
602
Step-by-step explanation:
18. 5)Find the sum of the integers from 8 and 35. 6) Find the sum of all even integers from 10 to 70. 7) Find the sum of all odd integers from 1 to 50. 8) Find the sum of the integers from 20 to 130 and are divisible by 5. 9) If the sum of the first 8 terms of an arithmetic sequence is 172 and its common difference is 3, what is the first term? 10) If the sum of the first 9 terms of an arithmetic sequence is 216 and its first term is 4, what is the common difference? answer properly
Answer:
The sum of the integers from 8 and 35 : 602
Further explanation
Arithmetic sequence is an arrangement of numbers that has the same difference for consecutive pairs of numbers or it can be said that "the difference between one term and the next is a constant. (adding the same number to the next number) "
The arrangement of the numbers is like this:
\tt a,a+d,a+2d,a+3d..etca,a+d,a+2d,a+3d..etc
a = initial term
d = different (common difference)
The formula for the nth term:
\tt \boxed{\bold{x_n=a+(n-1)d}}
x
n
=a+(n−1)d
While the formula for the sum of n terms:
\begin{gathered}\tt \boxed{\bold{\dfrac{1}{2}n(a+x_n)}}\\\\or\\\\\boxed{\bold{\dfrac{1}{2}n(2a+(n-1)d}}\end{gathered}
2
1
n(a+x
n
)
or
2
1
n(2a+(n−1)d
To calculate the number of integers between 2 numbers(the nth term), just subtract the two numbers then add 1
The number of integers between 8 and 35 :
\tt (35-8)+1=28~numbers(35−8)+1=28 numbers
So the sum of the integers from 8 and 35 :
n = 28
a = 8
xn = 35
\begin{gathered}\tt =\dfrac{1}{2}.28(8+35)\\\\=14(43)\\\\=\boxed{\bold{602}}\end{gathered}
=
2
1
.28(8+35)
=14(43)
=
602
Step-by-step explanation:
sana nakatulong po ito
19. find the sum integers from 8 and 35
Determine the sum of the integers from 8 and 35
Before discussing the problem, let us first know what is an integer? What is the definition of integer? What is the definition of an integer?
Integers are a collection of numbers whose shape is round. And integers are not decimal numbers, nor are they fractional numbers, but they can also be called full numbers. Integers are divided into 3, namely positive numbers, negative numbers, and neutral numbers, namely 0. Usually integers can be represented by a number line.
From the above definition, it can be understood that integers are a combination of the set of whole numbers and negative numbers, or a combination of natural numbers, 0, and negative numbers.
Integers are denoted by Z which comes from the word ZAHLEN (German) which means number.
After understanding the definition, let's discuss the problem: The sum of the integers from 8 and 35.
Is known:
a=8
[tex]a_{n}[/tex]=35
b=1
n=35-7=28
[tex]a_{n}=a+(n-1)b[/tex]
[tex]S_{n}=\frac{n}{2}(2a+(n-1)b)[/tex]
Asked:
[tex]S_{28}[/tex]=…
Answer:
[tex]S_{n}=\frac{n}{2}(2a+(n-1)b)[/tex]
[tex]S_{28}=\frac{28}{2}(2(8)+(28-1)1)[/tex]
[tex]S_{28}=\frac{28}{2}(16+27)[/tex]
[tex]S_{28}=\frac{28}{2}(43)[/tex]
[tex]S_{28}=(14)(43)[/tex]
[tex]S_{28}=602[/tex]
It turns out that the sum of the integers from 8 to 35 is 602. Let's look for it manually.
8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+ 33+34+35=…
35+8=43
34+9=43
33+10=43
………….
21+22=43
So the sum of these integers is 43x14=602.
Please note there is a question difference between:
1. Find the sum of the integers from 8 and 35
2. Find the sum of the integers between 8 and 35.
For the first question, the answer is like the answer above, while for the second question the numbers 8 and 35 are not counted. Why? Because the numbers between 8 and 35 are 9,10,11,12,…,33,34,35. So it is very important to pay attention to the language. Therefore it is necessary to be careful to understand the problem.
Hopefully this explanation is useful, and to further strengthen your understanding, please open the following link:
https://brainly.ph/question/21199284
#SPJ2
20. Find the sum of the integers from 8 and 35 with 21 terms
Answer:
(35+1−8)(8+35)2=
28×432=14×43=602Verify:8+35=439+34=4310+33=4311+32=4312+31=4313+30=4314+29=4315+28=4316+27=4317+26=4318+25=4319+24=4320+23=4321+22=4314 sums of 43=14×43=60221. 5) Find the sum of the integers from 8 and 35with solution
Answer:
43
Step-by-step explanation:
22. 5. Find the sum of the integers from 8 and 35.Solution:
Answer:
602
Step-by-step explanation:
Arithmetic Sequence
an = a1 + (n-1) d
35 = 8 + (n-1) 1
27 = n - 1
n = 28
Arithmetic Series
S28 = 28/2 (8 + 35)
S28 = 14 (43)
S28 = 602
hope it helps
23. find the sum of the integers from 8 to 35
Answer:
The sum of the integers from 8 and 35 is 602 .
24. Find the sum of the integers from 8 and 35
Answer:
602
Step-by-step explanation:
Answer:
602
Step-by-step explanation:
Arithmetic Sequence
an = a1 + (n-1) d
35 = 8 + (n-1) 1
27 = n - 1
n = 28
Arithmetic Series
S28 = 28/2 (8 + 35)
S28 = 14 (43)
S28 = 602
Hope it helped
25. 是身高Find the sum of the integers from 8 and 35.
Answer:
8 + 35 = 43
9 + 34 = 43
until 21 + 22 = 43
14 × 43 = 602
26. 1) Find the sum of the integers from 8 and 35.2) Find the sum of all even integers from 10 to 70.3) Find the sum of all odd integers from 1 to 50.please po yung matinong answer:>
Answer:
1. 602
2. 1184
3. 592
Step-by-step explanation:
8 + 9 + 10 +11 + ( eclipse )+ 34 + 35 = 602
10 + 12 + 14 + ( eclipse ) + 68 + 70 = 1184
1 + 3 + 5 + ( eclipse ) + 47 + 49 = 592
Hope It Helps
27. C) Answer what is asked.1) Find the sum of the first 13 terms of the sequence: -3, -1,1,3,...2) Find the sum of the first 15 terms of the arithmetic sequence:10, 15, 20, 25, ...?3) Find the sum of the first 11 terms of the arithmetic sequence:-4, 3, 10, 17,...?4) Find the sum of the first 19 terms of the arithmetic sequence:9, 14, 19, 24, ...?5) Find the sum of the integers from 8 and 35.6) Find the sum of all even integers from 10 to 70.7) Find the sum of all odd integers from 1 to 50.8) Find the sum of the integers from 20 to 130 and are divisible by 5.9) If the sum of the first 8 terms of an arithmetic sequence is 172 andits common difference is 3, what is the first term?10) If the sum of the first 9 terms of an arithmetic sequence is 216and its first term is 4, what is the common difference?
ANSWER:117675341102656715406251595115
1) Find the sum of the first 13 terms of the sequence: -3, -1,1,3,...
2) Find the sum of the first 15 terms of the arithmetic sequence:
10, 15, 20, 25, ...?
3) Find the sum of the first 11 terms of the arithmetic sequence:
-4, 3, 10, 17,...?
4) Find the sum of the first 19 terms of the arithmetic sequence:
9, 14, 19, 24, ...?
5) Find the sum of the integers from 8 and 35.
6) Find the sum of all even integers from 10 to 70.
7) Find the sum of all odd integers from 1 to 50.
8) Find the sum of the integers from 20 to 130 and are divisible by 5.
9) If the sum of the first 8 terms of an arithmetic sequence is 172 and
its common difference is 3, what is the first term?
10) If the sum of the first 9 terms of an arithmetic sequence is 216
and its first term is 4, what is the common difference?
ANSWER:11767534110265671540625159511528. (5) Find the sum of the integers from 8 and 35.
Answer:
tnong m kay batman82'(($?"!2"!"!3))
29. Answer what is asked.1) Find the sum of the first 13 terms of the sequence: −3, −1, 1, 3, …2) Find the sum of the first 15 terms of the arithmetic sequence: 10, 15, 20, 25, … ?3) Find the sum of the first 11 terms of the arithmetic sequence: −4, 3, 10, 17, … ?4) Find the sum of the first 19 terms of the arithmetic sequence: 9, 14, 19, 24, … ?5) Find the sum of the integers from 8 and 35.6) Find the sum of all even integers from 10 to 70.7) Find the sum of all odd integers from 1 to 50.8) Find the sum of the integers from 20 to 130 and are divisible by 5.9) If the sum of the first 8 terms of an arithmetic sequence is 172 and its common difference is 3, what is the first term?10) If the sum of the first 9 terms of an arithmetic sequence is 216 and its first term is 4, what is the common difference?
Answer:
1) 117
2) 675
3) 341
4) 1026
Step-by-step explanation:
using the formula An=a1+(n-1)d and An= n/2(a1+an)
30. 1.) Find the sum of the odd integers from -13 to 35, inclusive. 2.) Find the sum of the integers from -10 to 8 , exclusive. 3.) Cheryl opened 20,000.00-savings account in a bank. After three months, the money earned an interest of 125.00. Write an expression to represent the new balance in her savings account
Answer:
1.) Find the sum of the odd integers from -13 to 35, inclusive.This only means that you need to find the sum of the odd integers from -13 to 35 and both of them are included.[tex] \green{\boxed{- 13 + ( - 11) + ( - 9) + ( - 7) + ( - 5) + ( - 3) + ( - 1) +... + 35}}[/tex]
All you need is to add all of that numbers.But, if you want some easy way, we can use the formula in finding the Arithmetic Sequence and Series.
Given:A1 = -13 (first term)
An = 35 (last term)
d = -11 - (-13) = 2 (common difference)
n = ? (number of terms)
Sn = ? (sum of the sequence)
Solution:Find the number of terms[tex]An= A1 + (n-1)d \\ 35= -13+ (n-1)(2) \\ 35= -13+2n-2 \\ 35=-15+2n \\ 2n=35+15 \\ 2n=50 \\ n = 25[/tex]
Find the sum[tex]Sn= \frac{n(A1+An)}{2} \\ Sn= \frac{25(-13+35)}{2} \\ Sn= \frac{25(22)}{2} \\ Sn= \frac{550}{2} \\ Sn=275[/tex]
Therefore, the answer is 275.2.) Find the sum of the integers from -10 to 8 , exclusive.This only means that you need to find the sum from -10 to 8 and both of them is exclusive.[tex] \blue{\boxed{- 9 + ( - 8) + ( - 7) + ( - 6) + ( - 5) + ( - 4) + ( - 3) + ( - 2) + ( - 1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7}}[/tex]
All you need is to add all of that numbers.But, if you want some easy way, we can use the formula in finding the Arithmetic Sequence and Series.
Given:A1 = -9 (first term)
An = 7 (last term)
d = -8 - (-9) = 1 (common difference)
n = ? (number of terms)
Sn = ? (sum of the sequence)
Solution:Find the number of terms[tex]An= A1 + (n-1)d \\ 7= -9+ (n-1)(1) \\ 7= -9+n - 1 \\ 7=-10+n \\ n = 7 + 10 \\ n = 17[/tex]
Find the sum[tex]Sn= \frac{n(A1+An)}{2} \\ Sn= \frac{17(-9 + 7)}{2} \\ Sn= \frac{17( - 2)}{2} \\ Sn= \frac{ - 34}{2} \\ Sn= - 17[/tex]
Therefore, the answer is -17.3.) Cheryl opened 20,000.00-savings account in a bank. After three months, the money earned an interest of 125.00. Write an expression to represent the new balance in her savings account.[tex]\large\purple{\boxed{20000.00 + 125.00}}[/tex]
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